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Finding mmoles CH4/L of Culture |
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10-29-97 TSA |
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1. In a 160 ml bottle: 110 ml head space + 50 ml culture |
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In a 126 ml bottle: 76 ml head space + 50 ml culture |
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Sample size = 0.5 ml |
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2. Ht = height of methane peak in mm, Att = attenuation on machine |
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(Ht sample)(Attsample)=x |
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3. Measure 0.5 ml of 100% CH 4 (at about 1Atm) from gas tap three times. |
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(Ht Me)(AttMe) = y |
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x = z at about 1 Atm |
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y |
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4. At STP, 24 ml of gas = 1 mmol; therefore, for a 160 ml Balch bottle, |
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(110 ml head space)(z ) = (r ml) |
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(r ml)(1mmol/24ml) = q mmoles of gas |
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(q mmoles of gas)(1000ml) = p mmoles CH 4/L of culture |
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(50 ml of culture)(1 L) |
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5. Therefore, mmoles of CH 4/L of culture for a sample in a 160 ml Balch bottle is: (Attsample)(Htsample)(constant) = p mmoles CH4/L |
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160 ml bottle: |
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constant = (110 ml head space)(1000 ml)(1 mmol) |
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(50 ml of culture) (1 L) (24 ml) (Att Me)(HtMe) |
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126 ml bottle: |
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constant = (76 ml head space)(1000 ml)(1mmol) |
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(50 ml of culture) (1 L) (24 ml) (Att Me)(HtMe) |
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